9a^2+25a+16=a

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Solution for 9a^2+25a+16=a equation: 



9a^2+25a+16=a

We move all terms to the left:

9a^2+25a+16-(a)=0

We add all the numbers together, and all the variables

9a^2+24a+16=0

a = 9; b = 24; c = +16;
Δ = b2-4ac
Δ = 242-4·9·16
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$a=\frac{-b}{2a}=\frac{-24}{18}=-1+1/3$

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